Question

已知(a-2)的平方与|b+1|互为相反数,且-a+2b+m/2的值比1/2b-a+m的值多1,求m的值.

Answer 1

(a-2)^2=-|b+1| ==>a=2 b=-1

-a+2b+m/2=1/2b-a+m+1

-2-1+m/2=-1/2-2+m+1

m=3