1/(x-2)+3= (1-x)/(2-x)
(1+3x-6)/(x-2)=(x-1)/(x-2)
3x-5=x-1
得x=2 为增根
2/(x+1)-3/(x-1)=6/(x^2-1)
[2(x-1)-3(x+1)]/(x^2-1)=6/(x^2-1)
-x-5=6
得x=1 为增根
1/(x-2)+3= (1-x)/(2-x)
(1+3x-6)/(x-2)=(x-1)/(x-2)
3x-5=x-1
得x=2 为增根
2/(x+1)-3/(x-1)=6/(x^2-1)
[2(x-1)-3(x+1)]/(x^2-1)=6/(x^2-1)
-x-5=6
得x=1 为增根