Question

第八题,求数列的极限,

Answer 1

3*3^(1/2)*3^(1/4)*...*3^[1/2^(n-1)] = 3^[1+1/2+1/4+...+1/2^(n-1)] = 3^{[1-1/2^n]/(1-1/2)}

= 3^{2[1-1/2^n]} = 9^[1-1/2^n] -> 9^[ 1- 0] = 9.

第8题,极限为9