Question

求解……此题怎么用洛必塔法则求极限啊……

Answer 1

原式=limx→0 (tanx-x)'/(x^2tanx)'

=limx→0 (tan^2x)/(2xtanx+x^2)

=limx→0 1/[2x/tanx+(x/tanx)^2]

=1/(2*1+1^2)

=1/3.