Question

2x方-x+16分之1＝0 用公式法怎么解?

Answer 1

2x^2 - x + (1/16) = 0 ==> x = {-(-1) ±√[(-1)^2 - 4 * 2 * (1/16)]} / (2 * 2) ==> x = {1 ±√[1 - (1/2)] } / 4 ==> x = [1 ±√(1/2)] / 4 ==> x = [1 ± (√2) / 2] / 4 ==> x = 1/4 ± (√2)/8