x+y+z=a^2+b^2+c^2-2ab-2bc-2ca
2(x+y+z)=2a^2+2b^2+2c^2-2ab-2bc-2ca
2(x+y+z)=(a^2-2ab+b^2)+(b^2-2bc+c^2)+(c^2-2ca+a^2)
2(x+y+z)=(a-b)^2+(b-c)^2+(c-a)^2>0
所以x、y、z中至少有1个大于0
x+y+z=a^2+b^2+c^2-2ab-2bc-2ca
2(x+y+z)=2a^2+2b^2+2c^2-2ab-2bc-2ca
2(x+y+z)=(a^2-2ab+b^2)+(b^2-2bc+c^2)+(c^2-2ca+a^2)
2(x+y+z)=(a-b)^2+(b-c)^2+(c-a)^2>0
所以x、y、z中至少有1个大于0