一个孩子从倾角为23 °的滑滑梯上滑下,有摩擦的情况下在底部的速度是无摩擦情况下的五分之四.计算滑滑梯和孩子之间动摩擦系数.
mgh=mv1^2/2
mg(sin23-ucos23)h/sin23=mv2^2/2
v2=3*v1/5
Then u=0.27
一道英文物理题 结果就行A child slides down a slide with a 23° incline,a
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