计算:[(x+y)^2n]^4÷(-x-y)^2n+1
1个回答
[(x+y)^2n]^4÷(-x-y)^2n+1
=(x+y)^8n÷(x+y)^(2n+1)
=(x+y)^(8n-2n-1)
=(x+y)^(6n-1)
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