设There are five numbers为 A B C D E
则 A+B+C+D+E=5*9=45
1+2+C+D+E=5*8=40
2A+4B+C+D+E=13*5=65
解得 A=2
B=6
即 6 and 2 two numbers have been changed
设There are five numbers为 A B C D E
则 A+B+C+D+E=5*9=45
1+2+C+D+E=5*8=40
2A+4B+C+D+E=13*5=65
解得 A=2
B=6
即 6 and 2 two numbers have been changed