Question

已知复数z=根号3+i/(1-根号3i)平方,z 上面一横 是z共轭复数,则z*z的上面一横=

Answer 1

z=(√3+i)/(1-i√3）^2

z*z-=|z|^2=[|√3+i|/|(1-i√3)^2|]^2

=|√3+i|^2/[|1-i√3|^2}^2

=4/4^2=1/4.