X=2 Y=4 Do x=x*y y=y+1 Loop While y
1个回答
x=x*y=8
y=y+1=5
不满足循环条件
所以x=8
相关问题
[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x/4x²-y&
若x/x-1=y^2+4y-1/y^2+4y-2,y^2+4y-x=
(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y),其中x=4,y=1.5
(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y),其中x=4,y=1.5
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8
【4】(-2x+3y)(-2x-3y) 【5】(-1/4x-2y)(-1/4x+2y) 【6】x^2+(y-x)(y+x
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
求语句频度1.x=n;y=0;while(x>=(y+1)*(y+1)){@y++;}求@的语句频度2.x=91;y=1
(2x+y-1)²=(2x+y)²-2(2x+y)+1=4x²+4xy+y²-4