Question

解关于x的方程X2-(2k+3)x+k2+3k+2=0

Answer 1

x^2-(2k+3)x+k^2+3k+2=0

x^2-(2k+3)x+(k+1)(k+2)=0

[x-(k+1)][x-(k+2)]=0

x-(k+1)=0,x-(k+2)=0

x=k+1,x=k+2