(1)由于OA=OB=1,且角AOB=90度,故三角形AOB是等腰直角三角形
所以,角OAB=45度.
直线AB的解析式是x+y=1
(2)设E坐标是(m,1-m)
直线CE解析式是y=kx+b
(-1,0),(m,1-m)代入得到:
0=-k+b
1-m=km+b
1-m=k(m+1)
k=(1-m)/(1+m)
b=k=(1-m)/(1+m)
令X=0,y=b=(1-m)/(1+m)
即D坐标是(0,(1-m)/(1+m))
S(OCD)=1/2|OC||OD|=1/2*1*|(1-m)/(1+m)|
S(BDE)=1/2|BD||Xe|=1/2|1-(1-m)/(1+m)||m|
面积相等,则有1/2|(1-m)/(1+m)|=1/2|m|*|(2m)/(1+m)|
由于1-m>0,故有(1-m)/(1+m)=2m^2/(1+m)
1-m=2m^2
2m^2+m-1=0
(2m-1)(m+1)=0
m=1/2,m=-1(舍)
k=b=(1-1/2)/(1+1/2)=1/3
所以,CE的解析式是y=1/3x+1/3