原式=(X1-X2)+(3x1-3x2)/(x1x2)
=(X1-X2)+3(x1-x2)/(x1x2)
=(X1-x2)[1+3/X1X2]
怎么倒的(X1-X2)+3/X1-3/X2=(X1-x2)[1+3/X1X2]
1个回答
相关问题
-
1X2=1/3（1X2X3-0X1X2) 2X3=1/3(2X3X4-1X2X3) 发现1X2+2X3+3X4+、、、、
-
1.(x^3-1)/(x^3+2x^2+2x+1)+(x^3+1)/(x^3-2x^2+2x-1)-(2x^2+2)/(
-
变形：3/x2+1 - 3/x1+1怎么变成3 · (x1-x2) / (x1+1)·（x2+1）
-
x1^3 - x2^3=(x1-x2) (x1^2+x1x2+x2^2) 是怎么算的
-
1x2=1|3(1x2x3-0x1x2) 2x3=1|3(2x3x4-1x2x3) 3x4=1|3(3x4x5-2x3x
-
1x2=1/3(1x2x3=0x1x2 ) 2x3=1/3(2x3x4-1x2x3) 3x4=1/3(3x4x5- 2x
-
(x-1)/3-x/2=1 1-(2x)-1/5=x/3 (x-1)/2+1=x/3 2/3-8x=3-(1/2)x
-
三阶矩阵 [1,1,1；x1,x2,x3; x1^2,x2^2,x3^2]=(x2-x1)(x3-x1)(x3-x2)是
-
｛2X1-X2+3X3=33X1+X2-5X3=04X1-X2+X3=3X1+3X2-13X3=-6{X1-2X2+3X
-
1/(2-x)²,x/x²-4 1/3x(x-2),1/(x-2)(x+3),1/2(x+3)