已知:F=750N S=1m t=5s
求:W P
解:不知道图像,所以若两根绳子拉,则:W=F*2S=750N*2*1m=1500J
p=w/t=1500J/5s=300W
若根绳子拉,则:W=F*2S=750N*3*1m=2250J
p=w/t=2250J/5s=450W
已知:F=750N S=1m t=5s
求:W P
解:不知道图像,所以若两根绳子拉,则:W=F*2S=750N*2*1m=1500J
p=w/t=1500J/5s=300W
若根绳子拉,则:W=F*2S=750N*3*1m=2250J
p=w/t=2250J/5s=450W