f(x+2)是偶函数,即f(x+2)关于y轴对称,所以f(x)关于直线x=2对称,且f(x+2)=f(-x+2)
f[(兀-2)+2]=f(兀)=f[-(兀-2)+2]=f(兀-4)
f(x)在(0 2)上是增函数,
又0