已知a²+b²-10a-6b+34,求【(a-b)÷(a+b)】÷(a²-b²)

2个回答

  • a²+b²-10a-6b+34=0

    a²-10a+25+b²-6b+9=0

    (a-5)^2+(b-3)^2=0

    a=5

    b=3

    【(a-b)÷(a+b)】÷(a²-b²)÷(ab)×(a²+2ab+b²)÷(a²-ab)

    =[(a-b)/(a+b)]/[(a-b)(a+b)*ab]*(a+b)^2/a(a-b)

    =(a-b)/[(a+b)*(a-b)(a+b)*ab]*(a+b)^2/a(a-b)

    =(a-b)/[(a+b)^2*(a-b)*ab]*(a+b)^2/a(a-b)

    =(a-b)*(a+b)^2/[(a+b)^2*(a-b)*ab*a(a-b)]

    =(a-b)*(a+b)^2/[(a+b)^2*(a-b)^2*a^2b]

    =1/[(a-b)*a^2b]

    =1/[(5-3)*5^2*3]

    =1/(2*25*3)

    =1/150