1.a1+2a2+2^2a3+…+2^n-1an=n^2 (1)a1+2a2+2^2a3+...+2^(n-1)an+2^na(n+1)=(n+1)^2 (2)(2)-(1)2^n a(n+1)=2n+1a(n+1)=(2n+1)/2^nan=[2(n-1)+1]/2^(n-1)=(2n-1)/2^(n-1)数列{an}的通项公式为an=(2n-1)/2^(n-1)2.an=(2...
已知数列{an}满足a1+2a2+2^2a3+…+2^n-1an=n^2(n∈N*)
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