(a-2)(a²+2a+4)=a^3-2^3=a^3-8
(2x-y)(4x²+2xy+y²)=(2x)^3-y^3=8x^3-y^3
(a-b)(a²+2ab+b²)=a^3-b^3
∵4^m=y-1,9^n=x,
∴2^(2m+1)/3^(2n-1)=2×2^(2m)/[3^(2n)/3]
=2×4^m/(9^n/3)
=6(y-1)/x
=12
∴(y-1)/x=2,那么y=2x+1
(a-2)(a²+2a+4)=a^3-2^3=a^3-8
(2x-y)(4x²+2xy+y²)=(2x)^3-y^3=8x^3-y^3
(a-b)(a²+2ab+b²)=a^3-b^3
∵4^m=y-1,9^n=x,
∴2^(2m+1)/3^(2n-1)=2×2^(2m)/[3^(2n)/3]
=2×4^m/(9^n/3)
=6(y-1)/x
=12
∴(y-1)/x=2,那么y=2x+1