解x²+xy-2y²=0
(x²-y²)+(xy-y²)=0
(x+y)(x-y)+y(x-y)=0
(x-y)(x+y+y)=0
(x-y)(x+2y)=0
所以x-y=0 x=y
或者x+2y=0 x=﹣2y