(0.027)^3/2+(27/125)^-1/3-(2又7/9)^0.5 求值
1个回答
(0.027)^2/3+(27/125)^-1/3-(2又7/9)^0.5
=0.09+5/3-5/3
=0.09
相关问题
0.027^(-1/3)-(-1/6)^(-2)+256^(0.75)-(四又17/27)^(-1/3)+5/9^(-1
2.7*1.3=()*0.13=0.27*()=0.027*()=()*0.013
(4/9)0.5方+(-5.6)lg1方-(2又10/27)-2/3方+0.125-1/3方
3√0.125=_______3√-2又27分之10=______(3√0.5)³=______
2.7×1.3=3.51×0.13=0.27×?=0.027×?×0.013
计算:[(0.027)^-1/3]-[(-1/7)^-2]+[(25/9)^1/2]-(根号2-1)^0
一、1、³√-0.027+√0.16; 2、√4 - ³√125; 3、³√-8+√169
(-0.125)^12x(-1又2/3)^7x(-8)^13x(-3/5)^9
3.5+5/7*(0.4+2/3-4/9)*1.125
1.简便计算1.(54+9/13)除9 2.276*2/7除27.6 3.9.25*9.9+92.5%4.0.125*0