若2009/x+2010/y+2011/z=2000,3/x+2/y+1/z=12,则1/x+1/y+1/z=?
2个回答
2009/x+2010/y+2011/z
=2012/x+2012/y+2012/z-(3/x+2/y+1/z)
=2012(1/x+1/y+1/z)-12=2000
1/x+1/y+1/z=1
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