Question

在有理数范围内因式分解：x^5+x+1

Answer 1

X^5+X+1

＝x^5-x^2+x^2+x+1

=x^2(x^3-1)+(x^2+x+1)

=x^2*(x-1)(x^2+x+1)+(x^2+x+1)

=(x^2+x+1)(x^3-x^2+1)