Question

a+b+2的决对值与(2ab-1)^4互为相反数,求代数式(a+b )^2/3ab-3ab/(a+b)+1的值

Answer 1

a+b+2的绝对值与(2ab-1)^4互为相反数,

所以a+b=-2,

2ab=1,则ab=1/2

(a+b )^2/3ab-3ab/(a+b)+1

=(-2)^2/3*1/2-(3*1/2)/(-2)+1

=29/12

如果题目中[(a+b )^2/3ab]这里的3ab是分母,

(a+b )^2/3ab-3ab/(a+b)+1

=(-2)^2/(3*1/2)-(3*1/2)/(-2)+1

=53/12