x的平方-2+x分之1-x除以(x-2+x+2分之3),其中x等于2分之1
=(1-x)/(x²-2+x)÷[x-2+3/(x+2)]
=(1-x)/(x+2)(x-1)÷(x²-4+3)/(x+2)
=-1/(x+2)×(x+2)/(x-1)(x-3)
=-1/(x-1)(x-3)
=-1/(1/2-1)(1/2-3)
=-4/5;
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x的平方-2+x分之1-x除以(x-2+x+2分之3),其中x等于2分之1
=(1-x)/(x²-2+x)÷[x-2+3/(x+2)]
=(1-x)/(x+2)(x-1)÷(x²-4+3)/(x+2)
=-1/(x+2)×(x+2)/(x-1)(x-3)
=-1/(x-1)(x-3)
=-1/(1/2-1)(1/2-3)
=-4/5;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,