ax-3/2x^2<=1/6
-9x^2+6ax-1<=0
(3x-a)^2>=0,方程必有解,△>=0,a^2+6>=0(这貌似是废话?)
因为1/4<=x<=1/2时,y>=1/8,所以对称轴在1/4<=x<=1/2内,1/4<=a/(2*3/2)<=1/2
1/4<=a/3<=1/2
3/4<=a<=3/2
ax-3/2x^2<=1/6
-9x^2+6ax-1<=0
(3x-a)^2>=0,方程必有解,△>=0,a^2+6>=0(这貌似是废话?)
因为1/4<=x<=1/2时,y>=1/8,所以对称轴在1/4<=x<=1/2内,1/4<=a/(2*3/2)<=1/2
1/4<=a/3<=1/2
3/4<=a<=3/2