∵复数z 1满足(1+i)z 1=-1+5i,
∴ z 1 =
-1+5i
1+i =
(-1+5i)(1-i)
(1+i)(1-i) =2+3i
z 2=a-2-i,
∴ z 1 -
.
z 2 =4-a+2i ,
∵ | z 1 -
.
z 2 | < | z 1 | ,
∴a 2-8a-7<0,
∴1<a<7
故答案为:(1,7)
∵复数z 1满足(1+i)z 1=-1+5i,
∴ z 1 =
-1+5i
1+i =
(-1+5i)(1-i)
(1+i)(1-i) =2+3i
z 2=a-2-i,
∴ z 1 -
.
z 2 =4-a+2i ,
∵ | z 1 -
.
z 2 | < | z 1 | ,
∴a 2-8a-7<0,
∴1<a<7
故答案为:(1,7)