cos(α+7π/12)
=cos(-α-7π/12)
=sin[π/2-(-α-7π/12)]
=sin(α+13π/12)
=sin[π+(α+π/12)]
=-sin(α+π/12)
=-1/3
若sin(α+π/12)=1/3,则cos(α+7π/12)的值为
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