当n=1时,y=x 2-
3
2 x+
1
2 ,设y=x 2-
3
2 x+
1
2 =0的两根式a,b,
则a+b=
3
2 ,ab=
1
2 ,A 1B 1=
(a-b) 2 =
(a+b) 2 -4ab =
1
2 =1-
1
2 ,
当n=2时,y=x 2-
5
6 x+
1
6 ,同法可求出:A 2B 2=
1
6 =
1
2 -
1
3 ,
当n=3 时,y=x 2-
7
12 x+
1
12 ,同法可求出:A 3B 3=
1
12 =
1
3 -
1
4 ,
…
当n=2011 时,y=x 2-
4023
2011×2012 x+
1
2011 ×
1
2012 ,同法可求出:A 2011B 2011=
1
2011 ×
1
2012 =
1
2011 -
1
2012 ,
∴|A 1B 1|+|A 2B 2|+…+|A 2011B 2011|的值为1-
1
2 +
1
2 -
1
3 +
1
3 -
1
4 +…+
1
2011 -
1
2012 =1-
1
2012 =
2011
2012 ,
故选D.