Question

x+(1/x）=2若x^4+mx^2+1/3x^3+mx^2+3x=5求m的值

Answer 1

由x+(1/x)=2得x^2-2x+1=0,即(x-1)^2=0,得x=1

所以由x^4+mx^2+1/3x^3+mx^2+3x=5推出1+m+1/3+m+3=5

m=1/3