解:3x^2-2005x+2=0
2y^2-2005x+3=0
2y^2-2005y+3=0
2-2005(1/y)+3(1/y)^2=0
3(1/y)^2-2005(1/y)+2=0
3x^2-2005x+2=0
因为xy≠1,所以x≠1/y
所以x,1/y是方程3m^2-2005m+2=0的两个根
x+1/y=2005/3
x/y=2/3
x^2/y+x/y^2=(x/y)(x+1/y)=(2/3)×(2005/3)=4010/9
解:3x^2-2005x+2=0
2y^2-2005x+3=0
2y^2-2005y+3=0
2-2005(1/y)+3(1/y)^2=0
3(1/y)^2-2005(1/y)+2=0
3x^2-2005x+2=0
因为xy≠1,所以x≠1/y
所以x,1/y是方程3m^2-2005m+2=0的两个根
x+1/y=2005/3
x/y=2/3
x^2/y+x/y^2=(x/y)(x+1/y)=(2/3)×(2005/3)=4010/9