Question

如图,在等边三角形abc中,点D,E分别在BC,AC上,BD=CE,AD与BE相交于点F,求角AFE度数

Answer 1

∵△ABC是等边三角形,

∴∠ABC＝∠BCA＝60°,AB＝BC,

∵在△ABD和△BCE中,

AB＝BC,∠ABD＝∠BCE,BD＝CE,

∴△ABD≌△BCE,∴∠BAD＝∠CBE,

∵∠AFE＝∠BAD＋∠ABE,∴∠AFE＝∠CBE＋∠ABE＝∠ABC＝60°