(√3b-c)cosA=acosC等式两边同时除以三角形外接圆直径得:
(√3sinB-sinC)cosA=sinAcosC
===>√3sinBcosC=sinAcosC+sinCcosA
===>√3sinBcosA=sin(A+C)
===>√3sinBcosA=sinB
∴cosA=√3/3
(√3b-c)cosA=acosC等式两边同时除以三角形外接圆直径得:
(√3sinB-sinC)cosA=sinAcosC
===>√3sinBcosC=sinAcosC+sinCcosA
===>√3sinBcosA=sin(A+C)
===>√3sinBcosA=sinB
∴cosA=√3/3