(1)电磁炉5min消耗的电能:
W=
150
2000 ×3.6×10 6J=2.7×10 5J,
电磁炉的实际功率:
P=
W
t =
2.7×1 0 5 J
5×60s =900W;
(2)水吸收的热量:
Q 吸=c 水m(t-t 0)=4.2×10 3J/(kg•℃)×2.5kg×(50℃-30℃)=2.1×10 5J,
电磁炉烧水的效率:
η=
Q 吸
W =
2.1×1 0 5 J
2.7×1 0 5 J ≈77.8%.
答:(1)电磁炉的实际功率900W;
(2)电磁炉烧水的效率77.8%.