一吨碳酸钙是10000mol,需热1757000千焦,即4442.5molC,59.2千克,采纳了好吗
已知CaCO3(s)=CaO(s)+CO2(g);△H=-175.7kJ/mol。C(s)+O2(g)=CO2(g);△
2个回答
相关问题
-
已知 CaCO3(s)=CaO(s)+CO2(g);H=+175.7KJ/mol.C(s)+O2
-
已知 CaCO 3 (s)=CaO(s)+CO 2 (g) △H=+175.7 kJ/mol,
-
已知:C(s)+O2(g)=CO2(g) 变量H=-393.5kJ/mol,CaCO3(s)=CaO(s)+CO2(g)
-
①CaCO3(s)═CaO+CO2(g)△H=177.7kJ/mol
-
已知C(s)+O2(g)═CO2(g)△H=-393.5kJ/mol.煅烧1.00mol CaCO3生成CaO
-
已知:①CaCO 3 (s)═CaO (s)+CO 2 (g)△H=+178.2kJ•mol -1 ②2Na(
-
已知:C(s)+1/2O2(g)=CO(s)▲H=-110.35kj/mol C(s)+O2(g)=CO2(g)▲H=-
-
已知:C(s)+H 2 O(g)=CO(g)+H 2 (g) △H=a kJ/mol
-
已知:C(s)+O2(g)=CO2(g);△H=-393.5kJ/mol
-
(1)已知:① C(s)+O 2 (g)=CO 2 (g);△H=-393.5kJ·mol -1 ② 2CO(g)+O