1.T/2=8-2=6,∴ω=2π/T=2π/6=π/3
∵π/3×2+φ=π/2
∴φ=-π/6
∵A+c=2 -A+c=-4
∴A=3 c=-1
∴y=3sin(π/3x-π/6)-1
由-π/2+2kπ≤π/3x-π/6≤π/2+2kπ/2得,-1+6k≤x≤2+6k
∴单调递增区间是[-1+6k,2+6k]
已知函数y=Asin(ωx+φ)(A>0,.φ>0,|φ|
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