Question

出勤100人,请假5人,求出勤率

Answer 1

100/(100+5)=20/21 约为95.2%

设请假X人,则出勤39X,出勤率=39X/(39X+X)=97.5%

设原数X,X-X/100=39.6,X=39.6*100/99=40

100X-X=49.5,X=0.5

(6-5)/5=20%,(1/5-1/6)/(1/6)=1/5=20%

设乙1,则甲1+2/5=7/5,(乙-甲)/甲=-2/7

设未行1,则已行7/2,（7/2-1）/1=5/2=250%

(X+27)/(30+20)=0.92,X=19