如图,在矩形纸片ABCD中,AB=8,BC=6,点E在AB上,将△DAE沿DE折叠,使点A落在对角线BD上的点A′处,则

1个回答

  • 解题思路:

    A

    B

    =

    8

    BC

    =

    6

    B

    D

    =

    =

    10

    ,根据折叠可得:

    AD

    =

    A

    D

    =

    6

    A

    B

    =

    10

    6

    =

    4

    ,设

    AE

    =

    ,则

    A

    E

    =

    BE

    =

    ,在

    Rt

    A

    E

    B

    中:

    ,解得:

    。故答案为:

    3.

    3.

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