Question

通分 （1）6ab²分之x 9a²bc分之y （2）a²＋2a+1分之a-1 a&sup2

Answer 1

x/(6ab²)=x*（3ac)/(18a^2b^2c)= 3acx /(18a^2b^2c)

y/(9a²bc) = y*(2b)/(18a^2b^2c)= 2by /(18a^2b^2c)

(a-1)/(a²＋2a+1)=(a-1)^2/[(a+1)^2(a-1)]

b/(a^2-1)=b(a+1)/[(a+1)^2(a-1)]