假设全长为X(4/9)*X+300+(3/8)X-40=X得到X=14402. 设甲队人数为X, 乙队人数为YX=(4/5)Y(Y-16)*3/4=X+16X=-448Y=-560
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假设全长为X(4/9)*X+300+(3/8)X-40=X得到X=14402. 设甲队人数为X, 乙队人数为YX=(4/5)Y(Y-16)*3/4=X+16X=-448Y=-560