tanα(α+π/4)=2=(1+tana)/(1-tana)=2 tana=1/3
(2sinα+cosα)/(3cosα-2sinα)=(2tanα+1)/(3-2tanα)=(5/3)/(7/3)=5/7
已知tanα(α+π/4)=2,α(π,(3π/2)),则(2sinα+cosα)/(3cosα-2sinα)=
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