已知∠AOD=∠BOC=90°,且∠AOB=4∠COD,则∠COD=?
已知∠AOD=∠BOC=90°,∠AOB=4∠COD
∠AOB+4∠COD=360°-∠AOD-∠BOC
∠AOB+4∠COD=360°-90°-90°
∠AOB+4∠COD=180°
∠AOB=180°/5*4=144°
∠COD=∠AOB/4=144°/4=36°
答:
∠COD=36°
已知∠AOD=∠BOC=90°,且∠AOB=4∠COD,则∠COD=?
已知∠AOD=∠BOC=90°,∠AOB=4∠COD
∠AOB+4∠COD=360°-∠AOD-∠BOC
∠AOB+4∠COD=360°-90°-90°
∠AOB+4∠COD=180°
∠AOB=180°/5*4=144°
∠COD=∠AOB/4=144°/4=36°
答:
∠COD=36°