(1)由已知得:e^2=3/4=c/a,c^2=3/4*a^2,b^2=a^2-c^2=a^2-3/4*a^2=1/4*a^2, a=2b,又由菱形得:1/2*(2a)* (2b)=4,得:a*b=2,代入a=2b,得b=1,则a=2,得椭圆标准方程x^2/4+y^2=1.
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(1)由已知得:e^2=3/4=c/a,c^2=3/4*a^2,b^2=a^2-c^2=a^2-3/4*a^2=1/4*a^2, a=2b,又由菱形得:1/2*(2a)* (2b)=4,得:a*b=2,代入a=2b,得b=1,则a=2,得椭圆标准方程x^2/4+y^2=1.
满意请采纳