Question

（x4）的2次方加（x的2次方）的4次方－x乘以（x的2次方）的2次方乘以x的3次方－（－x）的3次方乘以（－x的2次方

Answer 1

(x^4)^2+(x^2)^4-x×[(x^2)^2]×(x^3)-{[(-x)^3]×[(-x)^2]^2}×(-x)

=x^8+x^8-x×(x^4)×(x^3)-[(-x^3)×(x^2)^2]×(-x)

=2x^8-x^8-(-x^3)×(x^4)×(-x)

=x^8-x^8

=0