=(x²+y²)/(x+y)²+(2/xy)÷[(x+y)²/x²y²]
=(x²+y²)/(x+y)²+(2/xy)×[x²y²/(x+y)²]
=(x²+y²)/(x+y)²+2xy/(x+y)²
=(x²+2xy+y²)/(x+y)²
=(x+y)²/(x+y)²
=1
=(x²+y²)/(x+y)²+(2/xy)÷[(x+y)²/x²y²]
=(x²+y²)/(x+y)²+(2/xy)×[x²y²/(x+y)²]
=(x²+y²)/(x+y)²+2xy/(x+y)²
=(x²+2xy+y²)/(x+y)²
=(x+y)²/(x+y)²
=1