(3x^2+2x+2)/(x^2+x+1)
=3-(x+1/2+1/2)/[(x+1/2)^2+3/4]
假设y=(x+1/2+1/2)/[(x+1/2)^2+3/4],x+1/2=t
yt^2-t+3y/4-1=0
△1^2-4y(3y/4-1)>=0
3y^1-2y-1
(3x^2+2x+2)/(x^2+x+1)
=3-(x+1/2+1/2)/[(x+1/2)^2+3/4]
假设y=(x+1/2+1/2)/[(x+1/2)^2+3/4],x+1/2=t
yt^2-t+3y/4-1=0
△1^2-4y(3y/4-1)>=0
3y^1-2y-1