limx->0 (1-cosxcos2xcos3x)/(x^2) 罗必塔
=limx->0 (sinxcos2xcos3x+2sin2xcosxcos3x+3sin3xcosxcos2x)/2x sinx~x
=limx->0 (1/2cos2xcos3x+2cosxcos3x+3*3/2cosxcos2x)
=7
limx->0 （1-cosxcos2xcos3x）/(x^2)
2个回答
相关问题
-
(1-cosxcos2xcos3x)/(1-cosx)当x趋近于0时的极限
-
limx→0xcos1/x等于多少
-
极限求详解!（1）limx→∞（2x+3)/(6x+1) (2) limx→0[√（1+x^2)-1]/x^2 (3)
-
极限求详解!（1）limx→0(tan2x)/(6x) （2）limx→1sin(x-1)/(√x-1) (3)limx
-
求极限(1-cosxcos2x...cosnx)/(x^2) (lim x->0)
-
1.limx→∞(1-1/2x)^x 2.limx→∞(1﹢x／x)^2x 3.limx→∞(1+1/x+3)^x 4.
-
求limx→0((2x+3)/(2x-1))∧x
-
limx-0(1-3根号1-x+x^2)/x
-
limx→0（x^3＋1）/（x＋1）sin2x
-
设f(x)={3x+2,x^2+1,2/x 联立 条件有x≤0,0≤x≤1,x＞1,求limx→0f(x)及limx→1