电阻率ρ=ρ0(1+αt)
ρ20=0.175=ρ0(1+αt)=ρ0*1.08
ρ0=0.0175/1.08=0.0162
ρ120=0.0162(1+120*0.004)
=0.0240
故R120=ρ120L/S
=0.024*200/10^-6
=4800000欧
电阻率ρ=ρ0(1+αt)
ρ20=0.175=ρ0(1+αt)=ρ0*1.08
ρ0=0.0175/1.08=0.0162
ρ120=0.0162(1+120*0.004)
=0.0240
故R120=ρ120L/S
=0.024*200/10^-6
=4800000欧