Question

x+2/x-2-16/(x-2)(x+2)-1/x+2,其中x=根号3-2

Answer 1

原式=[(x+2)²-16-(x-2)]/(x+2)(x-2)

=(x²+4x+4-16-x+2)/(x+2)(x-2)

=(x²+3x-10)/(x+2)(x-2)

=(x+5)(x-2)/(x+2)(x-2)

=(x+5)/(x+2)

=(√3-2+5)/(√3-2+2)

=(√3-3)/√3

=1-√3