是这样的：
对于两个连续的4的倍数,大的数字比小的数字的2倍小至少16.求这两个数的最小值.
设小的数字为x,则大的数字为x+4
列不等式：2x-(x+4)≥16
所以得x≥20
所以这两个数字最小值为20,24
For two consecutive multiples of 4,the larger number is less
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